Indeed this task is interesting! ;-P Instead of:
(i % 5 == 0)
another number can be used: 7,2, etc.
Here is my solution:
using System;
class NumbersInIntervalDividableByGivenNumber
{
static void Main()
{
Console.WriteLine("Please enter your 1st number:");
int start = int.Parse(Console.ReadLine());
Console.WriteLine("Please enter your 2nd number:");
int finish = int.Parse(Console.ReadLine());
int p = 0;
for (int i = start; i <= finish; i++)
{
if (i % 5 == 0)
{
Console.WriteLine(i);
p++;
}
}
Console.WriteLine("{0} numbers are dividible by 5: from {1} to {2}.", p, start, finish);
}
}