I need to write a program that enters 3 real numbers and prints them sorted in descending order (from bigger to smaller).

Nested if statements must be used. I don’t have to use arrays and the built-in sorting functionality.

Here are some examples:

 a b c result 5 1 2 5 2 1 -2 -2 1 1 -2 -2 -2 4 3 4 3 -2 0 -2.5 5 5 0 -2.5 -1.1 -0.5 -0.1 -0.1 -0.5 -1.1 10 20 30 30 20 10 1 1 1 1 1 1

asked in C# category

+1 vote
Try this code:

``` using System;

namespace Sort3NumbersWithNestedIfs
{
class Sort3NumbersWithNetsedIfs
{
static void Main()
{
double a = double.Parse(Console.ReadLine());
double b = double.Parse(Console.ReadLine());
double c = double.Parse(Console.ReadLine());

if ((a > b) && (a > c))
{
if (b > c)
{
Console.WriteLine("{0} {1} {2}", a, b, c);
}
else
{
Console.WriteLine("{0} {1} {2}", a, c, b);
}
}
else if ((b > a) && (b > c))
{
if (a > c)
{
Console.WriteLine("{0} {1} {2}", b, a, c);
}
else
{
Console.WriteLine("{0} {1} {2}", b, c, a);
}
}
else if ((c > a) && (c > b))
{
if (a > b)
{
Console.WriteLine("{0} {1} {2}", c, a, b);
}
else
{
Console.WriteLine("{0} {1} {2}", c, b, a);
}
}
}
}
}```
edited by user golearnweb
+1 vote

Or this one:

```using System;

class NumbersWithNestedIfs
{
static void Main()
{
Console.WriteLine("Please write 3 numbers:");
double a = double.Parse(Console.ReadLine());
double b = double.Parse(Console.ReadLine());
double c = double.Parse(Console.ReadLine());

if (a>b && a>c)
{
if (b>c)
{
Console.WriteLine("Descending order A: " + a + " " + b + " " + c);
}
else
{
Console.WriteLine("Descending order A1: " + a + " " + c + " " + b);
}
}
if (b>a && b>c)
{
if (a>c)
{
Console.WriteLine("Descending order B: " + b + " " + a + " " +c);
}
else
{
Console.WriteLine("Descending order B1: " + b + " " + c + " " +a);
}
}
if (c>a && c>b)
{
if (a>b)
{
Console.WriteLine("Descending order C: " + c + " " + a + " " + b);
}
else
{
Console.WriteLine("Descending order C1: " + c + " " + b + " " + a);
}
}
}
}```